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X^2+0X-4224=0
We add all the numbers together, and all the variables
X^2+X-4224=0
a = 1; b = 1; c = -4224;
Δ = b2-4ac
Δ = 12-4·1·(-4224)
Δ = 16897
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{16897}}{2*1}=\frac{-1-\sqrt{16897}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{16897}}{2*1}=\frac{-1+\sqrt{16897}}{2} $
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